25x^2=64x

Solution for 25x^2=64x equation:

25x^2=64x

We move all terms to the left:

25x^2-(64x)=0

a = 25; b = -64; c = 0;
Δ = b2-4ac
Δ = -642-4·25·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-64}{2*25}=\frac{0}{50}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+64}{2*25}=\frac{128}{50}
=2+14/25
$